When using a calorimeter, the initial…

Physics Questions

When using a calorimeter, the initial temperature of the metal is 70.4°C, and the initial temperature of the water is 23.6°C. At the end of the experiment, the final equilibrium temperature of the water is 29.8°C. What is the final temperature of the metal? What is the temperature change of the water? What is the temperature change of the metal?

Answer

1) 29.8 C The initial temperature of the metal is 70.4 C, which is higher than the water’s initial temperature of 23.6 C. When they are brought into contact, heat flows from the metal to the water until thermal equilibrium is achieved. At thermal equilibrium, both the metal and the water reach the same temperature, which is 29.8 C. Thus, the final temperature of the metal is 29.8 C. 2) 6.2 C The temperature change of the water can be calculated by taking the difference between its final temperature and its initial temperature: [tex]Delta T = T_f – T_i[/tex] where [tex]T_f = 29.8 C \ T_i = 23.6 C[/tex]. Plugging these values into the equation, we find [tex]Delta T=29.8 C-23.6 C=6.2 C[/tex]. The positive result indicates that the water’s temperature has increased. 3) -40.6 C To find the temperature change of the metal, we use the same formula: [tex]Delta T = T_f – T_i[/tex] where [tex]T_f = 29.8 C \ T_i = 70.4 C[/tex]. By substituting in these numbers, we get [tex]Delta T=29.8 C-70.4 C=-40.6 C[/tex]. The negative value signifies that the temperature of the metal has decreased.

Scroll to Top