Short Answer
The sample proportions for turtles with shell lengths greater than 2 feet are 0.375 for population D and approximately 0.1833 for population E, resulting in a difference of 0.1917. The standard deviation of this difference is approximately 0.0914, leading to a z-score of about 1.0029, with a probability of the difference being greater than 0.1917 calculated as approximately 0.1580.
Step 1: Calculate Sample Proportions
To find the sample proportions of turtles with shell lengths greater than 2 feet for both populations, use the formulas:
- The sample proportion for population D, denoted as pÀÜD, is calculated as: pÀÜD = 15/40 = 0.375.
- The sample proportion for population E, denoted as pˆE, is calculated as: pˆE = 11/60 ≈ 0.1833.
- The difference between these proportions is (pÀÜD – pÀÜE) = 0.375 – 0.1833 = 0.1917.
Step 2: Determine Mean and Standard Deviation
The mean of the difference in sample proportions is given as 0.1917. To compute the standard deviation, apply the formula:
- Standard deviation is calculated using: SD = ‚àö[(N_D * pÀÜD * (1 – pÀÜD) + N_E * pÀÜE * (1 – pÀÜE))].
- Plugging in the values gives: SD = ‚àö[(40 * 0.375 * (1 – 0.375) + 60 * 0.1833 * (1 – 0.1833))] ‚âà 0.0914.
Step 3: Calculate the Probability
To find the probability that the difference in sample proportions is greater than 0.1917, calculate the z-score and the associated probability:
- Use the formula Z = (pÀÜD – pÀÜE – (p_D – p_E)) / SD to find the z-score.
- This leads to: Z = (0.1917 – 0.1) / 0.0914 ‚âà 1.0029.
- Finally, find the probability: P(Z > 1.0029) = 1 – P(Z ‚⧠1.0029) ‚âà 0.1580.