At what angle above the horizontal…

Physics Questions

At what angle above the horizontal is a 15 N force, with a horizontal component of 4.5 N, directed?

Short Answer

The problem involves breaking down a force of 15 N at an angle into its horizontal (F cos θ) and vertical (F sin θ) components. Given that the horizontal component is 4.5 N, the angle θ is calculated using cos θ = 0.3, resulting in θ = 72.5° above the horizontal.

Step-by-Step Solution

Step 1: Understand the Force Components

In physics, when a force is applied at an angle, it can be broken down into two components: the horizontal component and the vertical component. For a force of magnitude F = 15 N at angle θ from the horizontal, these components are defined as follows:

  • Horizontal component: F cos Œ∏
  • Vertical component: F sin Œ∏

Step 2: Set Up the Equation for the Horizontal Component

Given that the horizontal component of the force is 4.5 N, we can create an equation to find the angle θ. This leads us to the equality where we substitute the known values:

  • Equation: F cos Œ∏ = 4.5 N
  • Substituting values: 15 N cos Œ∏ = 4.5 N

This simplifies to cos θ = 0.3.

Step 3: Calculate the Angle θ

To find the angle θ, we apply the inverse cosine function to the determined value:

  • Calculation: Œ∏ = cos‚Ū¬π(0.3)
  • Result: This leads us to the final angle of Œ∏ = 72.5¬∞ above the horizontal.

Related Concepts

Force components

The parts of a force that act in the horizontal and vertical directions, enabling the analysis of motion in each direction separately

Horizontal component

The portion of a force acting along the horizontal axis, calculated as the product of the force’s magnitude and the cosine of the angle with respect to the horizontal

Vertical component

The portion of a force acting along the vertical axis, calculated as the product of the force’s magnitude and the sine of the angle with respect to the horizontal.

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